Jan
28
theinfamouz asked:
A water balloon is dropped on some unsuspecting sunbathers from a stationary hot air balloon. The water balloon is 353 m above the beach. IF the water balloon accelerates downwards @ 9.81 m/s2, how long will it take to hit the beach.
What equation do I use?
I figured I’d just divide it and I got 35.98. It’d take 35.98 seconds, but I don’t my teacher wants me to do that.
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If you want to 


x = .5gt^2 + v0*t + x0 = .5(9.81)t^2.
353 = .5(9.81)t^2.
t = 8.48 seconds.
that would be right if its not accelerating (“accelerates downwards @ 9.81 m/s2″)
d=1/2 gt^2