balloon figures
theinfamouz asked:

A water balloon is dropped on some unsuspecting sunbathers from a stationary hot air balloon. The water balloon is 353 m above the beach. IF the water balloon accelerates downwards @ 9.81 m/s2, how long will it take to hit the beach.

What equation do I use?

I figured I’d just divide it and I got 35.98. It’d take 35.98 seconds, but I don’t my teacher wants me to do that.

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Comments

2 Responses to “A water balloon is dropped on some unsuspecting sunbathers ?”

  1. John on January 31st, 2010 9:50 am

    x = .5gt^2 + v0*t + x0 = .5(9.81)t^2.

    353 = .5(9.81)t^2.

    t = 8.48 seconds.

  2. K T on February 1st, 2010 8:38 am

    that would be right if its not accelerating (“accelerates downwards @ 9.81 m/s2″)

    d=1/2 gt^2

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